p^2+7p-2=5

Solution for p^2+7p-2=5 equation:

p^2+7p-2=5

We move all terms to the left:

p^2+7p-2-(5)=0

We add all the numbers together, and all the variables

p^2+7p-7=0

a = 1; b = 7; c = -7;
Δ = b2-4ac
Δ = 72-4·1·(-7)
Δ = 77
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{77}}{2*1}=\frac{-7-\sqrt{77}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{77}}{2*1}=\frac{-7+\sqrt{77}}{2}
$